If you take the votes of (Pres, VP, and Sec) as 1 coin flip.
With 18 random members, probability of 18 heads in a row is about 1 in 260,000
17 wallets out of 150 voted exactly the same as Chia list (10 persons).
20 wallets voted for Chia list (excluding Dona)
21 wallets voted for combination (Hiroki Koga "Ninja",Steve Li, Pedro Gutierrez, Anton Bosenko, Emerson Fonseca, William Tan). +1 wallets voted for almost all council members.
The intersection of 3 queries (sets) - 17 wallets. I’d say 20 wallets, because 3 didn’t vote for Treasurer - 100% winner.
if you exclude only William Tan from Chia Council member list - result will be 21
if you exclude only Steve Li from Chia Council member list - 21
if you exclude only Anton from Chia Council member list - 22
if you exclude only Pedro Gutierrez from Chia Council member list - 21
if you exclude only Ninja from Chia Council member list - 21
if you exclude only Emerson Fonseca from Chia Council member list - 23
It means 20 people voted for 6 councils as one unit. This is 100%
What is a probability that 20 people out of 150 will write 5 identical numbers from 1 to 21?
This election even broke math.