NEM Beta 0.6.82

Releases
#19

Done, but still same problem. Do I have to put same Port?

#20

You don’t see the message “NIS is synchronized!” at the top?

#21

Not, same NIS is not available, and I have closed and reopen all.

#22

Impossible ^^
Can you make a screenshot and post it here? also a screenshot of the settings.

#23

What I see is that I dont have an nem-0.6.82 folder only and old one nem-0.6.25

Nis nem.jpg1541×973 204 KB

#24

Host is still 127.0.0.1 ^^

#25

What that means?? :sweat_smile:

#26

means: change the “127.0.0.1” to “alice2.nem.ninja” in the settings :wink:

#27

hahhaha ok I see now, I feel stupid :sweat_smile: hehehhe, i thought you where saying me to put 127.0.0.1 because I had local i think.
Just put the “alice2.nem.ninja” and now NIS is synchronized! (at block 868213), thank you very much.

#28

Nice to hear it worked now :slight_smile:

#29

There is a proposal to verify the files (nis-ncc-0.6.x.tgz etc.) on the download page with Apostille service as owon did it. But not through nis-ncc-0.6.x.tgz.sig with Kleopatra or the like.

#30

I think it is a good idea too. It would be nice to get a good namespace representing core devs and use that to make Apostille notarizations. I personally would drag and drop it to verify before updating. That is one thing about Apostille, it is so easy.

#31

My PC is Win7 ,64bit, NEM 0.6.82 ,I run the runNCC.bat , failure to start .
It’s the Erro Message ,Anyone Can Help me
Caused by: java.lang.ClassCastException: java.lang.String cannot be cast to net.minidev.json.JSONObject
at org.nem.ncc.cache.AccountsFileRepository.tryLoad(AccountsFileRepository.java:57)
at org.nem.ncc.cache.AccountsFileRepository.load(AccountsFileRepository.java:42)
at org.nem.specific.deploy.appconfig.NccAppConfig.accountCache(NccAppConfig.java:184)
at org.nem.specific.deploy.appconfig.NccAppConfig$$EnhancerBySpringCGLIB$$558f545e.CGLIB$accountCache$15()
at org.nem.specific.deploy.appconfig.NccAppConfig$$EnhancerBySpringCGLIB$$558f545e$$FastClassBySpringCGLIB$$d0b6ade9.invoke()
at org.springframework.cglib.proxy.MethodProxy.invokeSuper(MethodProxy.java:228)
at org.springframework.context.annotation.ConfigurationClassEnhancer$BeanMethodInterceptor.intercept(ConfigurationClassEnhancer.java:309)
at org.nem.specific.deploy.appconfig.NccAppConfig$$EnhancerBySpringCGLIB$$558f545e.accountCache()
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
at java.lang.reflect.Method.invoke(Unknown Source)
at org.springframework.beans.factory.support.SimpleInstantiationStrategy.instantiate(SimpleInstantiationStrategy.java:162)
… 61 more
(org.nem.deploy.CommonStarter bootAndWait)

#32

@jackchan: delete the file accounts_cache_mainnet.json in the folder c:\users\ < your_user > \nem\ncc

#33

I would like to have this mosaic transaction fee formula to be clarified with a few examples. Suppose we have a Mosaic with a MosaicSupply above 10000, let’s say 20000 and a divisibility of 0.

What would the fee be for a transfer of 1 mosaic?
What would the fee be for a transfer of 10 mosaics?

#34

give me a testnet address and i send you some of those mosaics, then you can see what it costs to send those :slight_smile:

#35

To be a bit more specific:

  1. Max(1, Min(25, x * 900_000 / MosaicSupply) will always be 25 in your case because of the low supply, no matter if x is 1 or 10 or 1000
  2. floor(0.8 * ln(9_000_000_000_000_000 / MosaicSupply * 10^divisibility))) is 21 independent of x

So fee will always be 4 xem, no matter how many of those mosaics you transfer.

1 Like
#36

Yeah, that’s what i thought. And that was why I was thinking I must have miscalculated because it did not seem logical to charge a fee of 4 when you transfer 1 mosaic.
ok, thanks for the confirmation.

#37

Hello
I try to make calculate fee function by php.
But my function don’t work correctly.
The code is http://ideone.com/Cyf6kP

$divisibility = 1;
$quantity = 5;
$initialSupply = 10000;

echo max(1, min(25, $quantity * 900000 / $initialSupply) - floor(0.8 * log(9000000000000000 / $initialSupply * pow(10, $divisibility )))),"\n";
echo min(25, $quantity * 900000 / $initialSupply),"\n";
echo floor(0.8 * log(9000000000000000 / $initialSupply * pow(10, $divisibility ))),"\n";

For example ,I have namuyan:namu1 on testnet. I send 5 namu1.
divisibility=1
initialSupply =10000
Fee is 2 XEM ,but nanowallet say “Fee is 5 XEM”.
What is wrong ??

1 Like
#38

5 xem fee is correct i think.

max(1, min(25, 5 * 900000 / $initialSupply) = 25
floor(0.8 * log(9000000000000000 / $initialSupply * pow(10, $divisibility ))) = 20

2 Likes